x^2+1986x-32032=0

Solution for x^2+1986x-32032=0 equation:

x^2+1986x-32032=0

a = 1; b = 1986; c = -32032;
Δ = b2-4ac
Δ = 19862-4·1·(-32032)
Δ = 4072324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4072324}=2018$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1986)-2018}{2*1}=\frac{-4004}{2}
=-2002
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1986)+2018}{2*1}=\frac{32}{2}
=16
$